Network 1
L #number
L 0
==I
JC a001
TAK
L 1
==I
JC a002
TAK
L 2
>=I
BEC
Network 2
a001: L #Diameter
L 2.000000e+000
/R
SQR
L 3.141593e+000
*R
L #height
TAK
*R
T #Volume
BE
Network 3
a002: L #Diameter
L #height
-R
L #height
TAK
*R
T LD 0
L #Diameter
*R
L 3.141593e+000
*R
L 1.200000e+001
/R
T LD 4
L LD 0
SQRT
T LD 8
L #height
*R
L 4.000000e+000
*R
L 3.000000e+000
/R
T LD 12
L #height
SQR
L #height
*R
L 4.000000e+000
/R
L LD 8
/R
L LD 12
+R
T LD 16
L #height1
L #height2
+R
L LD 16
*R
L LD 4
+R
T #Volume
BE
程序的逻辑有什么问题么？当#number=0执行 Network 2，#number=1执行 Network 3，#number》=2执行结束该程序。请教给位老师，谢谢