发布于 2013-05-21 11:27:12
2楼
把20个值存储在连续的存储区域内,然后进行比较。
MD100存储最大值
MD104存储最小值
MD108是最大值除以最小值
以下程序及供参考
MD100:=DB100.DBD0
md104:=DB100.DBD0
for i=1 to 20 by 1
IF MD100 > DB100.DBD[ I ] then
:
else
MD100:=db100.dbd[i]
end_if;
end_for;
for i=1 to 20 by 1
IF MD104 > DB100.DBD[ I ] then
MD100:=db100.dbd[i]
end_if;
end_for;
md108:=md100/md104
every day is new day !