PLC 1200 步进电机无法旋转,是因为用脉冲下降沿触发么,如果是如何做?

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PLC 1200 步进电机无法旋转,是因为用脉冲下降沿触发么,如果是如何做?

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2017-12-11 16:22:32


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这是电机的驱动器说明书的内容,请各位帮下忙,看看怎么回事?

Maximum step frequency: 500 kHz

Minimum pulse width: 1 μs

A negative control pulse of 1 μs causes a motor step. The step is done with the falling

flank of the control pulse and the current is changed from run to stop current. If the time

between two control pulses is more than 40 ms, the stop current is activated.

The control pulse sequence must not suddenly start or stop, if the control pulse frequency

is higher than the start/stop frequency*) of the motor. Mispositioning of the drive would be

the result.

*) The start/stop frequency is defined as that frequency, from which a stepper motor can start from

standstill without losing a step. Typical values for the start/stop frequency are 200 to 2000 Hz. The

exact value depends on the load torque and the load inertia of the motor shaft.

If the motor is to be operated above the start/stop frequency range,


PLC 1200 步进电机无法旋转,是因为用脉冲下降沿触发么,如果是如何做? 已锁定
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