发布于 2005-07-09 01:28:38
0楼
G95 G90 G54 G00 X0 Y0 Z0
M03 S500
TOL(0.2,2)
G90
G0 X=0 Y=0
ROT X=-10 ;Einspannwinkel,max. 10grad
AROT Y=0
AROT Z=0
G9 G0 X=0 Y=0 Z=200 a3=0 b3=0 c3=1
G0 Z=0
M0
G0 Z=50 F0.1
G0 X=100
G0 a3=1 b3=0 c3= 0
G0 Z=0
;G0 X=40
G0 Z=-5 ;Schnittlage am Rohr
G0 X= 40.000 Y= 0 a3= 1.000 b3=0.000 c3=0.000 ;Startposition
M08
;G642
G1 X= 36.955 Y= 15.307 a3= 0.924 b3=0.383 c3=0.000
G1 Z=IC( -9.000)
G1 X= 15.307 Y= 36.955 a3= 0.383 b3=0.924 c3=0.000
G1 Z=IC( 9.000)
G1 X= -15.307 Y= 36.955 a3= -0.383 b3=0.924 c3=0.000
G1 Z=IC( -9.000)
G1 X= -36.955 Y= 15.307 a3= -0.924 b3=0.383 c3=0.000
G1 Z=IC( 9.000)
G1 X= -36.955 Y= -15.307 a3= -0.924 b3=-0.383 c3=0.000
G1 Z=IC( -9.000)
G1 X= -15.307 Y= -36.955 a3= -0.383 b3=-0.924 c3=0.000
G1 Z=IC( 9.000)
G1 X= 15.307 Y= -36.955 a3= 0.383 b3=-0.924 c3=0.000
G1 Z=IC( -9.000)
G1 X= 36.955 Y= -15.307 a3= 0.924 b3=-0.383 c3=0.000
G1 Z=IC( 9.000)
G1 X= 40.000 Y= 0 a3= 1.000 b3=0.000 c3=0.000 ;Enposition
G1 X= 36.955 Y= 15.307 a3= 0.924 b3=0.383 c3=0.000
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谭小波